No doubt about it.
If the chamber is resized to match the bore the accuracy will improve. Problem is this topic isn't about resizing the chamber to match the bore.
DennisA
I rechecked my math and I don't see a problem.
The answer represents two right triangles back to back and is calculated by obtaining the answer for one of the triangles and then doubling it.
In the case of the .454 diameter ball, the hypotenuse is the radius of the .454 diameter ball. The base of the triangle is the radius of the .447 diameter cylinder.
The square root of the radius of the hypotenuse squared minus the radius of the cylinder squared gives the length of the short leg of the triangle.
The radius of a .454 ball is .2270
The radius of the .447 chamber is .2235
The Square Root of the quantity .2270 squared minus .2235 equals .03971.
This is the distance from a line that is perpendicular to the bore passing thru the center of the ball with the answer representing either the forward end or the rearward end of the newly formed cylinder as measured from this perpendicular line.
Lets say it is the forward dimension. We must also add in the reward dimension which is the same value so we have .03971 + .03971 = .07942.
Looks good to me.