Here is where the train derails. You can only think of spin rate in terms like 1 turn in 48" while the projectile is still in the barrel. From the time it starts to move till it exits the muzzle it must turn at 1 revolution in 48" (let's assume a 48" long barrel for simplification). Let's use the data in Griz44Mag's post (#78) above. at exit from the muzzle the ball has the spin on it imparted by the 1 in 48" (or 1 in 4') rifling. It is now traveling at 1610 FPS and spinning at a rate of 24,120 RPM. We have converted the data to revolutions per minute and when dealing with RPM it doesn't matter whether the ball is moving or not Your big block Chev powered 53 Studebaker is sitting in the pits, you rev the engine to 7,500 RPM, vehicle speed 0 MPH, now at 1.5 miles the engine is doing 7,500 RPM and and the vehicle is traveling 208 MPH, the speed of the vehicle or the distance traveled has no bearing on RPM. As I posted before the formulas for angular velocity and angular momentum (spin speed and rotational momentum) do not deal with the distance, if any, traveled by the body, it can be stationary or traveling at the speed of light. The formula for angular acceleration, the change in rotational speed either accelerating or decelerating, refers to the change in RPM and it doesn't matter here either if the body is moving or not. The velocity at which the projectile is traveling is not relevant (the distance and time it took to travel from point A to point B) and attempting to drag them into the calculations will only cloud the issue to the point of zero visibility.
Gyroscopic action is not a force acting on the spin but rather is a result of the spin and mass of the spinning object and it in itself cannot change the rate of spin of the object as it in itself is not a force.
Everything slows but how much. Will 24000 RPM out last 1600 fps?