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One can always do the calculation. That's what I did for my table in the PDF file posted above.

Based on the calculation of the number grains in a 1" diameter ball of pure lead being equal to 1504 grains/(cubic inch) (1503.833) or 4.655 balls/ cubic inch, some relatively simple formulas can be derived. My source for the density of pure lead is based on the tables in the "Handbook of Chemistry and Physics: 1964). I don't think the density of pure lead has changed much.

The number of grains of a ball of a specific gauge, balls/pound or bore can be calculated as ball weight in grains = 7000 / gauge. Your spreadsheet formula should be of this form: =(7000/g)

The diameter of ball of a given weight in grains = cubed root of ((weight in grains)/1504 grains/(cubic inch))^(1/3)
The spreadsheet formula should be of this form: =(w/1504)^(1/3)

or

The diameter of a ball of given gauge = (4.655/gauge)^(1/3)
The spreadsheet formula should be of this form: =(4.655/gauge)^(1/3)
 
I have a 1985 Navy Arms 12 gauge double and the best I can tell the bores at the muzzle are 6.72”. Beyond about 3-4” the bore opens up but I have no way to measure them. This is just by feel on a bore brush. I suspect the barrels are full and full. Both barrels are stamped 12g. and 18.3. I recently acquired it here in the classifieds and haven’t had a chance to shoot. Anyone have a similar double?
 

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