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Sight question

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mikee51848

54 Cal.
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I did something rather dumb the other day. I had installed a new rear sight and was shooting a 50 yd target. I had a 3 inch group, including a bulls eye, but I wanted to notch the "V" a little more due to 58 year old eyes. So I did, and then shot 3 inches below the first group. :( Can I rectify this by lowering the front blade a little?
 
john12865 said:
Yes, that will work. File off just a little at a time.

Good advice, it is mush easier to remove metal than it is to add metal, it doesn't take much to change your point of impact at distance...
 
"...it doesn't take much to change your point of impact at distance..."
____________________________________

Right you are Musketman!

I'm guessing at the distance between your sights, but if they are spaced at 20 1/2 inches like the ones on my TC you will have to remove .034 from the front sight to raise the group 3 inches at 50 yards.

That is only a hair more than 1/32 of an inch!

If your sights are not 20 1/2 inches apart, multiply the real distance between your front sight and the rear sight by .0017 to determine how much material to remove from the front sight to raise the point of impact 3 inches at 50 yards. :)
 
Don't worry, if you file off too much from the front, you can always file on that rear notch again, and so on. :grin:
 
I got back to the range today and did some filing of the front sight. This is a 3 shot group, the first 3 shots, out of the barrel, at 50 yds, benchrest. Would you change anything? I tried a few at 100 yds., and well, lets just say I need a little practice! 2 were left in the #5 ring, about 8 o'clock and 1 was in the 6 ring, at 3 o'clock.
.50 cal, 65 gr 3F, Orig LV Lube.

Scan044July072006.jpg
 
Sight Calculator


A= The range in inches divided by the distance between the sights
in inches.

B = the amount you want to move the point of impact.

C= the amount you must raise or lower the front or rear sight.




You want to move the point of impact 6" at 100 yds that's


100 yds = 3600" , divided by a 36" sight radius = 100 that's [A]


6" divided by 100 = .06 that's .06 is [C]


B divided by A = C
 
Ye done confused me thar!
You listed what A is, then you give what C is then you say B divided by A equals C?

I guess it's just the letters that confuse me.
If I were saying it, I guess I would say:
Divide the distance to the target (in inches) by the distance between the sights (in inches). That's [A]

Divide [A] by the distance in inches you want the point of impact to move. The answer is the amount you have to move one of the sights.

Another way of doing the same thing is:
Divide the distance to the target (in inches) by the amount you want the point of impact to move (in inches). That's [D].
Multiply [D] by the distance between the sights (in inches). That gives the amount you have to move one of the sights.

Both methods result in the same answer. :)
 
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