Weight difference...3/4" .32 vs. 13/16" .36?

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Skychief

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For 'X' amount of barrel length, which weighs more: a 3/4" 32 caliber or a 13/16" 36 caliber (straight taper each)?

If a table exist of different diameter/caliber barrel weights, please direct me to it. As always, many thanks!
 
The 3/4 octagon X .32 caliber barrel will weigh about 0.108 pounds per inch of barrel length.

The 13/16 octagon X .36 caliber barrel will weigh about 0.125 pounds per inch of barrel length.
 
Skychief said:
For 'X' amount of barrel length, which weighs more: a 3/4" 32 caliber or a 13/16" 36 caliber (straight taper each)?

If a table exist of different diameter/caliber barrel weights, please direct me to it. As always, many thanks!

I'll tell ya what a tapered .36 makes a sweet gun. Now I custom ordered a barrel It has a 7/8" breech and tapers to 3/4" and is 34". it weighs 4lbs exactly I could have had it done with a different taper to make it lighter but I didn't want it to light and it built into a gun with a finished weight of 7lbs. Which for me, I find a 7 to 7 1/2lb gun just about perfecto for me. Thats why theres only 4 oz difference between my .36 and my .58 cal hunting rifle. Was sorta planned that way.

You can get a pretty light tapered barrel if you wanted one.
 
Skychief: You can find a table of barrel weights per inch in the back of the Dixie Guns Works Catalog.
 
Here's your equation:

Weight(octagon) = [d² - (d/(1+√2))² - π(c/2)²]* L * .283lb/in³

Where

d = diameter of barrel (flat to flat)
c = caliber of bore
L = length of barrel

Note, all measurements are inches. If you change measurements, you'd have to change the density as well.

If you had a round barrel, the weight would be expressed by:

Weight(round) = π[(d-c)/2]² * L * .283lb/in³

Similarly, if you had an octagon to round, you would calculate the weights of each section using the above formulas and add them together.

Edit: It's kind of hard to tell due to the font, but the π is pi, which is approximately 3.14159, or 3.14.

Also note, these are equations for straight barrels. For a taper, integration would be required, though the core of these equations would be the same, except that you'd have a ∆d/∆dL, which is to say a change in diameter as you go down the Length of the barrel.
 

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